simplify if
expression in checkidleinhibitor()
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88d386bfdc
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93a911d6e9
9
dwl.c
9
dwl.c
@ -588,16 +588,15 @@ chvt(const Arg *arg)
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void
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checkidleinhibitor(struct wlr_surface *exclude)
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{
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Client *c;
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int inhibited = 0;
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struct wlr_idle_inhibitor_v1 *inhibitor;
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wl_list_for_each(inhibitor, &idle_inhibit_mgr->inhibitors, link) {
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Client *c;
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if (exclude == inhibitor->surface)
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continue;
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/* In case we can't get a client from the surface assume that it is
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* visible, for example a layer surface */
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if (!(c = client_from_wlr_surface(inhibitor->surface))
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|| VISIBLEON(c, c->mon)) {
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if (exclude != inhibitor->surface
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&& (!(c = client_from_wlr_surface(inhibitor->surface))
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|| VISIBLEON(c, c->mon))) {
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inhibited = 1;
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break;
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}
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